x^2+0.27x-1.6*10^-19=0

Solution for x^2+0.27x-1.6*10^-19=0 equation:

x^2+0.27x-1.6*10^-19=0

We add all the numbers together, and all the variables

x^2+0.27x=0

a = 1; b = 0.27; c = 0;
Δ = b2-4ac
Δ = 0.272-4·1·0
Δ = 0.0729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.27)-\sqrt{0.0729}}{2*1}=\frac{-0.27-\sqrt{0.0729}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.27)+\sqrt{0.0729}}{2*1}=\frac{-0.27+\sqrt{0.0729}}{2}
$